What is the Kinetic Energy for the process stream with specifications give below?
Water flows into a process unit through a 3-cm ID (ID = inside diameter) pipe at a rate of 4 m3/h. Calculate the kinetic enegy for this stream in Watts.
Note: Quote answer with two decimal points.
4 m³/h x 1hr/3600 sec = 0.00111 m³/s
take one second.
density of water = 0.998 g/cm³ = 998 kg/m³
0.00111 m³ x 998 kg/m³ = 1.11 kg
what is the velocity of the water?
area is π(.0015)² = 7.06e-6 m²
length of a cylinder of volume 0.00111 m³ is
L = 0.00111 m³ / 7.06e-6 m² = 157 m
so velocity is 157 m/s
KE = ½mV² = ½(1.11)(157)² = 13686 Joules
since this occurs in one second, power is
13686 watts
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